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第2.7节  高阶导数

(2013-07-30 02:58:01)
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2.7 HIGHER DERIVATIVES

DEFINITION

          The second derivative of a real function f is the derivative of the derivative of f, and is denoted by f ''. The third derivative of f is the derivative of the second derivative, and is denoted by f '', or f(3). In general, the nth derivative of f is denoted by f(n).

 

If y depends on x, y =f(x), then the second differential of y is defined to be

                           d²y = f ′′(x) dx².

In general the nth differential of y is defined by

                           dny = f(n) (x)dx n.

Here dx² means (dx)²and dxn means (dx) n.

 

We thus have the alternative notations

第2.7节 <wbr> <wbr>高阶导数                 

 

 

 

For the second and nth derivatives. The notation

                             y''= f ''(x),    y(n) = f (n)(x),

is also used.

 

The definition of the second differential can be remembered in the following way. By definition,

                             dy= f '(x) dx.

Now hold dxconstant and formally apply the Constant Rule for differentiation, obtaining

                            d(dy) = f ''(x)dx dx,

or                        d²y= f ''(x)dx².

(This is not a correct use of the Constant Rule because the rule applies to a real constant c, and dx is not a real number. It is only a mnemonic device to remember the definition of d²y, not a proof.)

 

The third and higher differentials can be motivated in the same way. If we hold dxconstant and formally use the Constant Rule again and again, we obtain

第2.7节 <wbr> <wbr>高阶导数

 

 

 

 

 

and so on.

 

The accelerationof a moving particle is defined to be the derivative of the velocity with respect to time,

                   a = dv/dt.

 

Thus the velocity is the first derivative of the distance and the acceleration is the second derivative of the distance. If s is distance, we have

第2.7节 <wbr> <wbr>高阶导数

 

 

 

EXAMPLE  A ball thrown up with initial velocity b moves according to the equation

                                y = bt - 16t ²

 

with y in feet, t in seconds. Then the velocity is

                      v= b -32 t ft/sec,

and the acceleration (due to gravity) is a constant,

                      a= -32 ft/sec².

 

EXAMPLE  2  Find the second derivative of y=sin(2θ).

     First derivative  Put u=2θ. Then

第2.7节 <wbr> <wbr>高阶导数                    

            

By the Chain Rule,

第2.7节 <wbr> <wbr>高阶导数

 

 

 

 

 

 

 Second derivative  Let v=2cos (2θ). We must find dv/dθ.Put u= 2 θ. Then

第2.7节 <wbr> <wbr>高阶导数           

                          v=2 cos u,          

 Using the Chain Rule again,

第2.7节 <wbr> <wbr>高阶导数                          

 

 The simplifies to

第2.7节 <wbr> <wbr>高阶导数

 

                       

 

EXAMPLE  3 A particle moves so that at time t it has gone a distance s along a straight line, its velocity is v, and its acceleration is a. Show that

第2.7节 <wbr> <wbr>高阶导数             

 

 

第2.7节 <wbr> <wbr>高阶导数By definition we have 

     

 

第2.7节 <wbr> <wbr>高阶导数So by the Chain Rule,

            

 

  

 EXAMPLE  If a polynomial of degree nis repeatedly differentiated, the kth derivative will be a    

          polynomial of degree n -k for k n, and the (n+1)st derivative will be zero. For example,

 

                           

 

第2.7节 <wbr> <wbr>高阶导数

 

 

 

 

 

 

 

 

Geometrically, the second derivative f ′′(x)is the slope of the curve y= f(x)and is also the rate of change of the slope of the curve y=f(x).

 

PROBLEMS  FOR  SECTION 2.7

   y=1/x                               y=x5                     y=__________

   f(x)=3x -2                            f(x)= x1/2 + x -1/2           f(t)= t 3 - 4t 2

   f(t) =_____                           y=(3t - 1)10               y=sin x

10   y= cos x                           11   y=A sin (Bx)

12   y= A cos (Bx)                      13  y=e ax

14   y=e -ax                            15 y=1n x

16  y= x 1n                          17______________

18   y=_________    19_____________    20______________

21   z=_______    22 _____________    23_______________

24   Find the third derivative of y= x² - 2/x.

25   A particle moves according to the equation s= 1-1/, t >0. Find its acceleration.

26   An object moves in such a way that when it has moved a distance sits velocity is v=____.

     Find its acceleration. (Use Example 3.)

27   Suppose udepends on x and d²u/dx²exists. If y = 3u, find d²y/dx²

28   If d²u/dx²and v/dx²exist and y=u+v, find d²x/dx².

29   if d²u/dx²exists and y=u², find d²y/dx².

30   if d²u/dx²and d²v/dx²exist and y=uv, find d²y/dx².

31   Let y=ax2 + bx +c be a polynomial of degree two. Show that dy/dxis a linear function and d²y/dx²is

     constant function.

32 Prove that the nth derivative of a polynomial of degree n is constant. (Use the fact that the derivative

     of a polynomial of degree kis a polynomial of degree k-1.)

 

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