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第6.7节  反常积分

(2013-07-18 16:56:35)
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6.7  IMPROPER  INTEGRALS

What is the area of the region under the curve y=1/______from x= 0 to x=1 (Figure 6.7.1(a)) ? The function 1/_____is not continuous at x= 0, and in fact 1/_____is infinite for infinitesimal ε>0. Thus our notion of a definite integral does not apply. Nevertheless we shall be able to assign an area to the region using improper integrals. We see from the figure that the region extends infinitely far up in the vertical direction. However, it becomes so thin that the area of the region turns out to be finite.

 

The region of Figure 6.7.1(b) under the curve y=x -3from x=1 to x=

第6.7节 <wbr> <wbr>反常积分

第6.7节 <wbr> <wbr>反常积分

 

 

 

 

 

 

 

 

 

 

 

Figure 6.7.1

 

extends infinitely far in the horizontal direction. We shall see that this region, too, has a finite area which is given by an improper integral.

 

Improper integrals are defined as follows.

 

DEFINITION

        Suppose f is continuous on the half - open interval [a, b]. The improper integral of f from a to b is defined by the limit

 

 

 

If the limit exists the improper integral is said to converge. Otherwise the improper integral is said to diverge.

 

The improper integral can also be described in terms of definite integrals with hyperreal endpoints. We first recall that the definite integral

 

 

 

is a real function of two variables uand v. If u and v vary over the hyperreal numbers instead of the real numbers, the definite integral ____f(x)dx stands for the natural extension of Devaluated at (u,v),

                      

 

 

 

Here is description of the improper integral using definite integrals with hyperreal endpoints.

 

Let f be continuous on (a, b].

(1) ___  f(x)dx= S if and only if __ f(x) dxS for all positive infinite ε.

(2) ______ f(x) dx =(or -) if and only if ___ f(x) d(x) is positive infinite (or negative infinite) for all

   positive infinite ε.

 

EXAMPLE 1  Find ________.For u > 0,

 

                          

 

 

             Then 

 

             Therefore the region under the curve y=1/____ from 0 to 1 shown in Figure 6.7.1(a) has area 2,

             and the improper integral converges.

 

EXAMPLE 2   Find ________dx. For u >0,

                

 

 

This time

 

 

 

The improper integral diverges. Since the limit goes to infinity we may write

                         ______ x-2dx =

The region under the curve in Figure 6.7.2 is said to have infinite area.

 

第6.7节 <wbr> <wbr>反常积分Warning: we remind the reader once again that the symbolsand -are not real or even hyperreal numbers. We use them only to indicate the behavior of a limit, or to indicate an interval without an upper or lower endpoint.

 

 

 

 

 

 

 

 

6.7.2

EXAMPLE 3  Find the length of the curve y=x2/3, 0 x 8. From Figure 6.7.3 the curve must have finite length. However, the derivative

                              ____________________

 

is undefined at x=0. Thus the length formula gives an improper integral,

 

 

 

 

 

第6.7节 <wbr> <wbr>反常积分

 

 

 

 

 

 

 

 

Figure 6.7.3

 

Let u=9x2/3+ 4, du = 6x-1/3dx. The indefinite integral is

 

 

Therefore

 

 

 

Notice that we use the same symbol for both the definite and the improper integral. The theorem below justifies this practice.

 

THEOREM 1

If f is continuous on the closed interval [a,b] then the improper integral of f from a to b converges an equals the definite integral of f from a to b.

 

PROOF We have shown in Section 4.2 on the Fundamental Theorem that the function

                      F(u) = ____ f(x)dx

        is continuous on [a, b]. Therefore

 

 

 

          where ___f(x)dxdenotes the definite integral.

We now define a second kind of improper integral where the interval is infinite.

 

DEFINITION

        Let f be continuous on the half-open interval[a,∝). The improper integral of f from a to ∝ is defined by the limit

 

 

 

        The improper integral is said to converge if the limit exists and to diverge otherwise.

 

Here is description of this kind of improper integral using definite integrals with hyperreal endpoints.

 

          Let f be continuous on [a,∝).

 

  (1) ___ f(x)dx =S if and only if ___ f(x) dxS for all positive infinite H. 

  (2) ___ f(x)dx =(or -)if and only if ___ f(x) dx is positive infinite (or negative infinite ) for all positive

     infinite H.  

 

EXAMPLE 4  Find the area under the curve y= x-3from 1 to. The area is given by the improper integral

 

 

For

 

Thus

 

 

 

So the improper integral converges and the region has area___. The region is shown in Figure 6.7.1(b) and extends infinitely far to the right.

 

EXAMPLE 5  Find the area under the curve y= x-2/3, 1 x≤ ∝.

 

 

 

The region is shown in Figure 6.7.4 and has infinite area.

 

第6.7节 <wbr> <wbr>反常积分

 

 

 

Figure 6.7.4

EXAMPLE 6

        The region in Example 5 is rotated about the x-axis. Find the volume of the solid of revolution.

       

        We use the disc method because the rotation is about the axis of the independent variable. The volume

        formula gives us an improper integral.

 

 

 

        So the solid shown in Figure 6.7.5 has finite volume V=3π.

 

第6.7节 <wbr> <wbr>反常积分

 

 

 

 

 

 

 

 

Figure 6.7.5

 

The last two examples give an unexpected result. A region with infinite area is rotated about the x-axis and generates a solid with finite volume! In terms of hyperreal numbers, the area of the region under the curve y= x-2/3from 1 to an infinite hyperreal number His equal to 3( H1/3-1), which is positive infinite. But the volume of the solid of revolution from 1 to His equal to

                    3π(1 - H-1/3),

Which is finite and has standard part 3π.

 

We can give a simpler example of this phenomenon. Let Hbe a positive infinite hyperinteger, and form a cylinder of radius 1/Hand length H²(Figure 6.7.6). Then the cylinder is formed by rotating a rectangle of length H², width 1/H, and infinite area H²/H=H. But the volume of the cylinder is equal to π,

 

             V= π r²h = π(1/H)²(H=π.

 

第6.7节 <wbr> <wbr>反常积分

Imagine a cylinder made out of modelling clay, with initial length and radius one. The volume is π. The clay is carefully stretched so that the cylinder gets longer and thinner. The volume stays the same, but the area of the cross section keeps getting bigger. When the length becomes infinite, the cylinder of clay still has finite volume V=π, but the area of the cross section has become infinite.

 

There are other types of improper integrals. If f is continuous on the half - open interval [a,b] then we define

                       _______ f(x)dx =________f(x)dx.

 

If f is continuous on (-∝,b] we define

                         _______f(x)dx =________f(x)dx.

 

We have introduced four types of improper integrals corresponding to the four types of half - open intervals

[a,b),     [a,∞),   (a,b]  ( -,b].

 

By piecing together improper integrals of these four types we can assign an improper integral to most functions which arise in calculus.

 

DEFINITION

      A function f is said to be piecewise continuous on an interval I if f is defined and continuous at all but perhaps finitely many points of I. In particular, every continuous function is piecewise continuous.

 

We can introduce the improper integral ____ f(x)dx whenever f is piecewise continuous on I and a,b are either the endpoints of I or the appropriate infinity symbol. A few examples will show how this can be done.

 

Let f be continuous at every point of the closed interval[a,b] except at one point c where a We define

          

                   _______ f(x)dx= _____ f(x)dx+ ____ f(x)dx.

 

EXAMPLE 7

        Find the improper integral ____ x -1/3 dx. x -1/3 is discontinuous at x=0. The indefinite integral is

           x-1/3 dx = ___ x2/3 + C.

Then

 

 

Similarly,

 

 

So

 

 

and the improper integral converges. Thus, the region shown in Figure6.7.7 has finite area.

第6.7节 <wbr> <wbr>反常积分

 

 

 

 

 

 

 

 

Figure 6.7.7

 

If f is continuous on the open interval (a, b), the improper integral is defined as the sum

 

 

 

where c is any point in the interval (a,b). The endpoints a and b may be finite or infinite. It does not matter which point c is chosen, because if e is any other point in (a,b), then

 

 

 

EXAMPLE  8 Find

 

 

 

The function 2/______ +1/____ is continuous on the open interval (0, 2)but discontinuous at both endpoints (Figure 6.7.8). Thus

 

 

 

 

第6.7节 <wbr> <wbr>反常积分

 

 

 

 

 

 

 

 

 

Figure 6.7.8

First we find the indefinite integral.

 

 

 

Then

 

 

Also

 

 

Therefore

 

 

 

EXAMPLE 9  Find

 

 

 

The function 1/x² + 1/(x-1)² is continuous on the open interval (0,1) but discontinuous at both endpoints. The indefinite integral is

 

 

We have

 

 

 

Similarly we find that

 

 

 

In this situation we may write

 

 

 

and we say thttp://www.google.com/hat the region under the curve in Figure 6.7.9 has infinite area.

 

 

第6.7节 <wbr> <wbr>反常积分

 

 

 

 

 

 

 

 

 

Figure 6.7.9

Remark In Example 9

We are faced with a sum of two infinite limits. Using the rules for adding infinite hyperreal

numbers as a guide we can give rules for sums of infinite limits.

 

    If H and K are positive infinite hyperreal numbers and c is finite, then

                           H + K is positive infinite,

                           H + c is positive infinite,

                           -H - K is negative infinite,

                           -H + c is negative infinite,

H-K can be either finite, positive infinite, or negative infinite.

第6.7节 <wbr> <wbr>反常积分By analogy, we use the following rules for sums of two infinite limits or of a finite and an infinite limit. These rules tell us when such a sum can be considered to be positive or negative infinite. We use the infinity symbols as a convenient shorthand, keeping in mind that they are not even hyperreal numbers.

                        

                        

 

 

 

 

 

 

 

EXAMPLE 10 Find _____ xdx. We see that 

 

         

 

 

            and                  ______ xdx = ∞.

            Thus ____ xdx diverges and has the form ∞-∞. We do not assign it any value or either of the symbols ∞ or -∞. The region under the curve f(x)=x is shown in Figure 6.7.10.

第6.7节 <wbr> <wbr>反常积分

 

 

 

 

 

 

 

 

 

 

 

Figure 6.7.10

 

It is tempting to argue that the positive area to the right of the origin and the negative area to the left exactly cancel each other out so that the improper integral is zero. But this leads to a paradox.

 

Wrong: _____ xdx =0. Let v= x+2, dv= dx. Then

 

 

 

 

 

 

Subtracting          

 

But                       ______ 2dx=∞

So we do not give the integral_____ xdx the value 0, and instead leave it undefined.

 

PROBLEMS  FOR  SECTION 6.7

In Problems 1-36, test the improper integral for convergence and evaluate when possible.

 

1_________x -2dx                2________x-0.9 dx

3________x -1/2dx                 4______(2x- 1)-3dx
5______(2x- 1)-3dx                 6_______x -1/3 dx     

7______x2+ 2x-1dx                8_________x -2 - x -3 dx

9__________ x(1+x2)-2 dx           10 _______ x -1/2+ x-2dx

11________x -1/2+ x-2dx ??          12_________x-2dx

13 _______(x-1) -2/3 dx              14 ________x-2dx

15 _____x -2/3 dx                   16 ______dx

17____2x(x2-1) -1/3 dx              18____2x3 dx 

19_____(2x-1) -2/3 dx                20_____(3x-1) -5 dx 

21______x²dx                    22 ______(2x-1 )3 dx

23_________dx                   24_______x -1/3 dx

25 ________ x3 dx                26 _______x -3/2 dx

27________ dx                    28______ |x| (x + 1) -3 dx

29_________dx                   30_______(x-1 )-2 + (x-3) -2 dx

31____ (x-1)-1/2 + (3-x) -1/2 dx        32______dx

33__________                    34____________

35_________f(x)dx   where f(x)= ______  

 

36  _________f(x)dx   where f(x)= ______ 

37  Show that if r is a rational number, the improper integral ____ x-r dx converges when r <1

    and diverges when r >1.

38  Show that if r is a rational, the improper integral ____ x-r dx converges when r >1

    and diverges when r <</i>1.

39  Find the area of the region under the curve y=4x-2 from x=1 to x=∝.

40  Find the area of the region under the curve y=1/_______ from x=_____ to x=1.

41  Find the area of the region between the curves y=x-1/4 and y=x-1/2from x=0 to x=1.

42  Find the area of the region between the curves y= -x-3 and y=x -2, 1 ≤ x<∝.

43  Find the volume of the solid generated by rotating the curve y=1/x, 1 ≤ x<∝,

    about (a) the x-axis, (b) the y-axis.

44   Find the volume of the solid generated by rotating the curve y=x-1/3, 0 ≤ x<1,

     about (a) the x-axis, (b) the y-axis.

45   Find the volume of the solid generated by rotating the curve y=x-3/2, 0 ≤ x<4,

     about (a) the x-axis, (b) the y-axis.

46   Find the volume generated by rotating the curve y=4x-3, -∝ ≤ x< -2, about (a) the x-axis,

     (b) the y-axis.

47   Find the length of the curve y=_____ from x=0 to x=1.

48   Find the length of the curve y=_____ from x=0 to x=1.

49   Find the surface area generated when the curve y=___________, 0 ≤x ≤1, is rotated about

     (a) the x-axis, (b) the y-axis.

50   Do the same for the curve y=______ , 0 ≤ x ≤1

51   (a) Find the surface area generated by rotating the curve y= ____ , 0 ≤x ≤1, about the x-axis.

     (b)Set up an integral for the area generated about the y-axis.

52   Find the surface area generated by rotating the curve y=x2/3, 0 ≤x ≤ 8, about the x-axis.

53   Find the surface area generated by rotating the curve y=_______, 0 ≤xa, about (a) the

     x-axis, (b) the y-axis (0< ar).

54   The force of gravity between particles of mass m1 and m2 is F= gm1 m2 / where s is the

     distance between them. If m1 is held fixed at the origin, find the work done in moving m2

     from the point (1,0) all the way out the x-axis.

55   Show that the Rectangle and Addition Properties hold for improper integrals.

 

EXTRA  PROBLEMS  FOR  CHAPTER 6

 

The skin is peeled off a spherical apple in four pieces in such a way that each horizontal cross section is a

   square whose corners are on the original surface of the apple. If the original apple had radius r, find the

   volume of the peeled apple.

Find the volume of a tetrahedron of height h and base a right triangle with legs of length a and b.

 

Find the volume of the wedge formed by cutting a right circular cylinder of radius r with two planes, meeting

   on a line crossing the axis, one plane perpendicular to the axis and the other at a 45°angle.

 

Find the volume of a solid whose base is the region between the x-axis and the curve y=1-x², and which

   intersects each plane perpendicular to the x-axis in a square.

 

In Problems 5-8, the region bounded by the given curves is rotated about (a) the x-axis, (b) the y-axis. Find the volumes of the two solids of revolution.

 

   y=0  y=________, 0x1

   y=0  y=x3/2     0x1

   y= x,   y= 4-x,      0x2

   y=xp,  y=xq,        0x1   where 0< q < p

The region under the curve y=______, 0x1, where 0<</span> p, is rotated about the x-axis. Find the volume of

   the solid of revolution.

10 The region under the curve y=(x²+4 )1/3, 0x2, is rotated about the y-axis. Find the volume of the solid of

   Revolution.

11 Find the length of the curve  y= (2x +1)3/2, 0x2.

12 Find the length of the curve  y= 3x -2, 0x4.

13 Find the length of the curve  x=3t+1, y=2-4t, 0t1.

14 Find the length of the curve  x=f(t), y=f(t)+c, atb.

15Find the length of the line    x=At+B, y= Ct + D, atb.

16 Find the area of the surface generated by rotating the curve y=3x²-2, 0x1, about the y-axis.

17 Find the area of the surface generated by rotating the curve x=At²+Bt, y=2At +B,0t1, about the x-axis.

   A>0, B >0.

18 Find the average value of f(x)= x/ _______ , 0x4.

19Find the average value of f(x)= xp 1xb p -1.

20 Find the average distance from the origin of a point on the parabola y=x²,  0x4.

   With respect to x.

21 Given that f(x) = xp, 0x1, p a positive constant, find a point cbetween 0 and 1 such that f(c)equals the average value of f(x)

22 Find the center of mass of a wire on the x-axis, 0x2, whose density at a point xis equal to the square of the distance from (x,0) to (0,1).

23 Find the center of mass of a length of wire with constant density bent into three line segments covering the top, left, and right edges of the square with vertices (0,0), (0,1), (1,1), (1,0).

24 Find the center of mass of a plane object bounded by the lines y=0,y=x,x=1, with density p(x)=1/x.

25 Find the center of mass of a plane object bounded by the curves x=y², x=1, with density p(x)=y².

26 Find the centroid of the triangle bounded by the x-and y-axes and the line ax+by = c, where a, b, and c are

   positive constants.

27 A spring exerts a force of 10x1bs when stretched a distance x beyond its natural length of 2ft. Find the work required to stretch the spring from a length of 3 ft to 4ft.

 

In Problems 28-36, test the improper integral for convergence and evaluate if it converges.

 

28     _________ x-3 dx                        29 ____(x+2) -1/4 dx

30     ____x - 4dx                            31____x -1/5dx

32     ____x 1/5dx                            33__________ dx

34     ________ dx                           35 ________dx

36     _____ sin x dx

37      A wire has the shape of a curve y=f(x), axb, and has density p(x)at value x

        Justify the formulas below for the mass and moments of the wire.

 

                      

 

38  Find the mass, moments, and center of mass of a wire bent in the shape of a parabola

 

        y=x²,  -1 x 1, with density p(x)=________.

 

39  Find the mass, moments, and center of mass of a wire of constant density pbent in the

shape of the semicircle y=________  -1 x1.

40 An object fills the solid generated by rotating the region under the curve y=f(x), axb, about the x-axis.

Its density per unit volume is p(x). Justify the following formula for the mass of the object.

 

                      m= _____ p(x) π (f(x))² dx.

41 A container filled with water has the shape of a solid of revolution formed by rotating the curve x=g(y),

     ayb, about the (vertical) y-axis.Water has constant density pper unit volume.

     Justify the formula below for the amount of work needed to pump all the water to the top of the container.

                                 W=______ (g(y))² (b-y) dy.

 

  42 Find the work needed to pump all the water to the top of a water-filled container in the shape of a cylinder

     with height h and circular base of radius r.

  43 Do Problem 46 if the container is in the shape of a hemispherical bowl of radius r.

  44 Do Problem 46 if the container is in the shape of a cone with its vertex at the bottom,

     height h, and circular top of radius r.

 45 The pressure, or force per unit area, exerted by water on the walls of a container is equal to

  p=p(b-y) where p is the density of water and b-ythe water depth. Find the total force on a dam in the

  shape of a vertical rectangle of height band width w,assuming the water comes to the top of the dam.

 46 A water-filled container has the shape of a solid formed by rotating the curve x=g(y), aybabout

      the (vertical) y-axis. Justify the formula below for the total force on the walls of the container.

 

 

 

 

 

 

 

 

 

 

 

 

 

 

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