EXAMPLE 1 Find the length of the
curve
y=2x 3/2, 0 ≤
x≤ 1
Shown in Figure 6.3.3. We
have
dy/dx = 3x1/2,_________________
Put u=1+9x.
Then
___________________

Figure
6.3.3
Sometimes a curve in the
(x,y) plane is given by parametric
equations
x=f(t),
y=g(t),
c ≤ t ≤
d.
A natural example is the
path of a moving particle where is time. We give a formula for the
length of such a
curve.
DEFINITION
Suppose the
functions
x =
f(t), y =
g(t)
Have continuous derivatives and the parametric
curve does not retrace its path for t in [a, b]. The length of the
curve is defined by
JUSTIFICATION
The infinitesimal piece of the curve
(Figure 6.3.4) from t to t+ Δt

is almost a straight
line, so its lengthΔs is given
by
__________________
(compared to
Δt),
__________________
(compared to
Δt),
By the Infinite Sum
Theorem,
______________________
The general formula for
the length of a parametric curve reduces to our first formula when
the curve is given by a simple equation
x=g(y) or y=
f(x).
If
y=f(x), a≤ x≤
b, we take x=tand
get
____________________
If
x=g(y), a≤ y≤
b, we take y=tand
get
________________
EXAMPLE
2 Find the length of the path of a ball whose
motion is given by
x=
20t, y= 32t -
16t²
fromt=0 until the ball hits the ground.(Ground
level isy=0, see Figure 6.3.5). The ball is
at
ground level
when
32t -16t² =0, t=0 and
t=2.
We
have
dx / dt = 20, dy / dt =
32-32t,
We cannot evaluate this integral yet, so the
answer is left in the above form. We can get an approximate answer
by the Trapezoidal Rule. When x = ____ , the Trapezoidal
Approximation is
s ~
53.5
error ≤ 0.4,

Figure
6.3.5
The following example shows
what happens when a parametric curve does retrace its
path.
EXAMPLE
3 Let
x = 1- t²,
y=1,
-1 ≤ t ≤
1.
As
tgoes from -1 to 1, the point
(x,
y) moves from (0,1) to
(1,1) and then back along the same line to (0, 1) again. The path
is shown in Figure
6.3.6.

The path has length one.
However, the point goes along the path twice for a total distance
of two. The length formula gives the total distance the point
moves.
We next prove a theorem
which shows the connection between the length of an arc and the
area of a sector of a circle. Given two points
Pand Qon a circle with center
O, the arc PQis the portion of the circle traced out by a
point moving from P toQin a counterclockwise direction. The
sector POQ
is the region bounded by
the arc PQand the radii
OPandOQas shown in Figure
6.3.7.

Figure
6.3.7
THEOREM
Let
Pand Q be two points on a circle with
center O. The area Aof the sector
POQis equal to one half the
radius rtimes the length
s of the arc PQ,
A=____ rs.
DISCUSSION
The theorem is intuitively plausible because
if we consider an infinitely small arc
Δsof the circle as in Figure 6.3.8, then the
corresponding sector is almost a triangle of
height rand base Δs, so it has
area
ΔA ≈
____rs.
( compared to Δs ).
DISCUSSION The
theorem is intuitively plausible because if we consider an
infinitely small arc Δs of the circle as in Figure 6.3.8, then the
corresponding sector is almost a triangle of height r and base Δs,
so it has area
ΔA
≈ ____rΔs.
(compared to Δs).
Summing up, we expect that A
= _____rs.

We can
derive the formula C = 2πr for the circumference of a circle
using the theorem. By definition, π is the area of a circle of
radius one,
_____________________
Then a
circle of radius r has area
______________________
Therefore the circumference C is given by
____________________
PROOF OF
THEOREM
To simplify notation assume that the
center O is at the origin, P is the
point
(0, r) on the x-axis, and
Q is a point (x, y) which varies along the
circle
(Figure 6.3.9). We may take y as
the independent variable and PROBLEMS
FOR SECTION
6.3
Find the lengths of the following
curves.
1
y= _____(x+2)3/2,
0≤ x ≤
3
2 ·y= (x²+_____)3/2,
-2≤ x ≤
5
3
(3y - 1)2 =
x3, 0≤
x ≤
2
4 y= (4/5)
x5/4,
0≤ x ≤
1
5
y=(x-1)2/3,
1 ≤ x ≤
9
hint: Solve for x as a function of y.
6
y= _____,
1≤ x ≤
3
7 x= _____
, 3≤ y ≤
6
8
y= _____,
1≤ x ≤
100
9 y= _____,
1≤ x ≤
8
10
8x=2y4 + y-2, 1≤ y ≤
2
11 x2/3
+ y2/3 =1, first
quadrant
12
y=_________dt, 0≤
x ≤ 10
13
y=_________dt, 2≤
x ≤ 6
14
y=_________dt, 1≤
x ≤ 3
15
x=_________dt, 1≤
y ≤ 4
16
y=_________dt, 0≤
x ≤ 1
17 Find the
distance travelled from t=0 to t=1 by an object whose
motion
is x= t3/2
18 Find the
distance moved from t=0 to t=1 by a particle whose
motion
is given by x= 4(1-t)3/2, y= 2t
3/2.
19 Find the distance travelled
from t=1 to t=4 by an object whose
motion
is given by x= t 3/2, y= 9t
.
20 Find the distance travelled
from time t=0 to t=3 by a particle whose
motion
is given by the parametric equations x=
5t2, y= t 3.
21 Find the distance moved from
t=0 to t= 2π by an object whose
motion
is x= cos t, y=
sin t
.
22 Find the distance moved from
t=0 to t= π by an object with
motion
x= 3cos 2t, y=
3 sin 2t
.
23 Find the distance moved from
t=0 to t= 2π by an object with
motion
x= cos²t, y=
sin²t
.
24 Find the distance moved by an
object with motion
x= et cos t, y= et
sin t . 0≤ t ≤
1.
25 Let A(t) and
L(t) be the area under the curve y=x² from x=0
to x=t, and the
length of the curve from x=0 to
x=t, respectively. Find
d(A(t))/d(L(t)).
In Problems 26-30, find definite integrals for the
lengths of the curves, but do not evaluate the
integrals.
26
y=x3,
0≤ x≤1
27
y=2x2 - x + 1, 0≤ x ≤
4
28
x=1/t, y=t²
, 0≤ t≤5
29
x=2t +
1,
y=____, 1≤ t ≤
2
30 The
circumference of the ellipse x² + 4y² =
1
31 Set up
integral for the length of the curve y=____, 1≤ x≤ 2 , and find
the
Trapezoidal Approximation where
Δx=___.
32 Set up an
integral for the length of the curve x= t² -
t, y = ____t
3/2,
0≤ t ≤ 1 , and find the Trapezoidal
Approximation where Δt=___.
33 Set up an
integral for the length of the curve y= 1/x, 1≤
x ≤ 5 , and find the
Trapezoidal Approximation where
Δx=1
34 Set up an
integral for the length of the curve y= x², -1≤
x ≤ 1 , and find
the Trapezoidal Approximation where
Δx=_____
□35 Suppose the same curve is
given in two ways, by a simple equation
y=F(x), a≤x≤b and by parametric
equations x= f(t), y=g(t), c≤ t
H≤d.
Assuming all derivatives are continuous
and the parametric curve does
not retrace its path, prove that the two
formulas for curve length give the
same values. Hint: Use integration
by change of variables.

Figure
6.3.9
Use the equation x= __________ for the right half of the circle. Then
A
and s depend on y. Our plan
is to show that
__________________
First,
we find dx/dy:
________________________
Using
the definition of arc length,
________________________
The
triangle OQR in the figure has area____xy, so the sector has
area
_________________________
Then ________________________________________
Thus _________________________________________
So
A and ____ differ and only by a
constant. But when y=0, A=___ rs =
0.
Therefore A = ___ rs.
To
prove the formula A=___ rs for arcs which are not
within a single quadrant we simply cut the arc into four pieces
each of which is within a single quadrant.
PROBLEMS
FOR SECTION
6.3
Find the lengths of the following
curves.
1
y= _____(x+2)3/2,
0≤ x ≤
3
2 ·y= (x²+_____)3/2,
-2≤ x ≤
5
3
(3y - 1)2 =
x3, 0≤
x ≤
2
4 y= (4/5)
x5/4,
0≤ x ≤
1
5
y=(x-1)2/3,
1 ≤ x ≤
9
hint: Solve for x as a function of y.
6
y= _____,
1≤ x ≤
3
7 x= _____
, 3≤ y ≤
6
8
y= _____,
1≤ x ≤
100
9 y= _____,
1≤ x ≤
8
10
8x=2y4 + y-2, 1≤ y ≤
2
11 x2/3
+ y2/3 =1, first
quadrant
12
y=_________dt, 0≤
x ≤ 10
13
y=_________dt, 2≤
x ≤ 6
14
y=_________dt, 1≤
x ≤ 3
15
x=_________dt, 1≤
y ≤ 4
16
y=_________dt, 0≤
x ≤ 1
17 Find the
distance travelled from t=0 to t=1 by an object whose
motion
is x= t3/2
18 Find the
distance moved from t=0 to t=1 by a particle whose
motion
is given by x= 4(1-t)3/2, y= 2t
3/2.
19 Find the distance travelled
from t=1 to t=4 by an object whose
motion
is given by x= t 3/2, y= 9t
.
20 Find the distance travelled
from time t=0 to t=3 by a particle whose
motion
is given by the parametric equations x=
5t2, y= t 3.
21 Find the distance moved from
t=0 to t= 2π by an object whose
motion
is x= cos t, y=
sin t
.
22 Find the distance moved from
t=0 to t= π by an object with
motion
x= 3cos 2t, y=
3 sin 2t
.
23 Find the distance moved from
t=0 to t= 2π by an object with
motion
x= cos²t, y=
sin²t
.
24 Find the distance moved by an
object with motion
x= et cos t, y= et
sin t . 0≤ t ≤
1.
25 Let A(t) and
L(t) be the area under the curve y=x² from x=0
to x=t, and the
length of the curve from x=0 to
x=t, respectively. Find
d(A(t))/d(L(t)).
In Problems 26-30, find definite integrals for the
lengths of the curves, but do not evaluate the
integrals.
26
y=x3,
0≤ x≤1
27
y=2x2 - x + 1, 0≤ x ≤
4
28
x=1/t, y=t²
, 0≤ t≤5
29
x=2t +
1,
y=____, 1≤ t ≤
2
30 The
circumference of the ellipse x² + 4y² =
1
31 Set up
integral for the length of the curve y=____, 1≤ x≤ 2 , and find
the
Trapezoidal Approximation where
Δx=___.
32 Set up an
integral for the length of the curve x= t² -
t, y = ____t
3/2,
0≤ t ≤ 1 , and find the Trapezoidal
Approximation where Δt=___.
33 Set up an
integral for the length of the curve y= 1/x, 1≤
x ≤ 5 , and find the
Trapezoidal Approximation where
Δx=1
34 Set up an
integral for the length of the curve y= x², -1≤
x ≤ 1 , and find
the Trapezoidal Approximation where
Δx=_____
□35 Suppose the same curve is
given in two ways, by a simple equation
y=F(x), a≤x≤b and by parametric
equations x= f(t), y=g(t), c≤ t
H≤d.
Assuming all derivatives are continuous
and the parametric curve does
not retrace its path, prove that the two
formulas for curve length give the
same values. Hint: Use integration
by change of variables.