高考备考:求切点弦所在直线方程的方法与解析
| 分类: 高考专栏 |
命题1:已知圆O:
http://5b0988e595225.cdn.sohucs.com/images/20181218/00201710bd2d43769291c1c3bd941158.jpeg
上一点M(
http://5b0988e595225.cdn.sohucs.com/images/20181218/a9484fc362a54d0e805817ffcc792004.jpeg
),则以点M为切点的圆的切线方程为
http://5b0988e595225.cdn.sohucs.com/images/20181218/2f7262106317443dbe51e86465064da2.jpeg
。
命题2:已知两相交圆
http://5b0988e595225.cdn.sohucs.com/images/20181218/ba40e652e6ec4fb581e7faa771fa2f81.jpeg
:
http://5b0988e595225.cdn.sohucs.com/images/20181218/78fb93c326754640b6dbe34a47a0f640.jpeg
,圆
http://5b0988e595225.cdn.sohucs.com/images/20181218/319a8d4aab5d4cbeae50a409ecf34f09.jpeg
,则两圆的公共弦所在的直线方程为
http://5b0988e595225.cdn.sohucs.com/images/20181218/01dbca2a3f5944ec99cb9d7e2628cab5.jpeg
例、已知点P(
)为圆O:
http://5b0988e595225.cdn.sohucs.com/images/20181218/00201710bd2d43769291c1c3bd941158.jpeg
外一点,过点P作圆的切线
http://5b0988e595225.cdn.sohucs.com/images/20181218/5e777bf125734efc9ecfc68870cf0f9a.jpeg
,其中
http://5b0988e595225.cdn.sohucs.com/images/20181218/0eb0203008804e6088a7e5aa1278d149.jpeg
为切点,求切点弦
http://5b0988e595225.cdn.sohucs.com/images/20181218/91dc06675bdb4a369d89b29f735d05e0.jpeg
所在的直线方程。
http://5b0988e595225.cdn.sohucs.com/images/20181218/5b24776cc22f42d3bc461e8921d139d5.jpeg
解法1:由题意知
http://5b0988e595225.cdn.sohucs.com/images/20181218/1d4146e3e98c46dca3163be84f15131e.jpeg
所以,O、
http://5b0988e595225.cdn.sohucs.com/images/20181218/ff68bfb2e3e54c4783c7d5a0980ef8f4.jpeg
、P、
http://5b0988e595225.cdn.sohucs.com/images/20181218/e7687878d0e04d0a81f5e60c67f53d69.jpeg
四点共圆
http://5b0988e595225.cdn.sohucs.com/images/20181218/ec93adb6c8bf4d4299f18be491e4099c.jpeg
,且OP为此圆的直径,即圆
http://5b0988e595225.cdn.sohucs.com/images/20181218/ec93adb6c8bf4d4299f18be491e4099c.jpeg
:
http://5b0988e595225.cdn.sohucs.com/images/20181218/a56c963a6a8448f6b21e2a5b83e4493d.jpeg
即
http://5b0988e595225.cdn.sohucs.com/images/20181218/7774d2813bff4f5eaa9291e468b0cde2.jpeg
又
http://5b0988e595225.cdn.sohucs.com/images/20181218/91dc06675bdb4a369d89b29f735d05e0.jpeg
为圆O、圆
http://5b0988e595225.cdn.sohucs.com/images/20181218/ec93adb6c8bf4d4299f18be491e4099c.jpeg
的公共弦,由命题2知,切点弦
http://5b0988e595225.cdn.sohucs.com/images/20181218/91dc06675bdb4a369d89b29f735d05e0.jpeg
所在直线方程为
http://5b0988e595225.cdn.sohucs.com/images/20181218/6269f743c3d840b6bdf4b01075ddd4d6.jpeg
。
解法2:设
http://5b0988e595225.cdn.sohucs.com/images/20181218/2298e9d62307406388ccea286e7ff63d.jpeg
由命题1得,
http://5b0988e595225.cdn.sohucs.com/images/20181218/2ddf1948b8a74ef8a15ad7ddea99ebe6.jpeg
方程为
http://5b0988e595225.cdn.sohucs.com/images/20181218/ec2b600bdcfb441eb2bbffe73cba717e.jpeg
方程为
http://5b0988e595225.cdn.sohucs.com/images/20181218/dae7b56b2d644be68bddd45fe5de0490.jpeg
。
由
http://5b0988e595225.cdn.sohucs.com/images/20181218/c56b6c0441794d54ad1f615e525d67b3.jpeg
,可得
http://5b0988e595225.cdn.sohucs.com/images/20181218/8f43e6f8c5ff4f5789c5bac31cf59a31.jpeg
http://5b0988e595225.cdn.sohucs.com/images/20181218/c12fc60129594e3b96ec99da23140dd4.jpeg
两点坐标都满足关于
http://5b0988e595225.cdn.sohucs.com/images/20181218/0ca1a62649c143ddb09e5bde53004020.jpeg
的二元一次方程
http://5b0988e595225.cdn.sohucs.com/images/20181218/6269f743c3d840b6bdf4b01075ddd4d6.jpeg
,而过
http://5b0988e595225.cdn.sohucs.com/images/20181218/0eb0203008804e6088a7e5aa1278d149.jpeg
两点的直线有且只有一条,因此,切点弦
http://5b0988e595225.cdn.sohucs.com/images/20181218/91dc06675bdb4a369d89b29f735d05e0.jpeg
所在直线方程为
http://5b0988e595225.cdn.sohucs.com/images/20181218/6269f743c3d840b6bdf4b01075ddd4d6.jpeg
。
解法3:如上图,设
http://5b0988e595225.cdn.sohucs.com/images/20181218/86b2f2bd858e451db179e7b5a3eaf820.jpeg
容易证明
http://5b0988e595225.cdn.sohucs.com/images/20181218/790cd3e8625347888817e2aa4742f9ae.jpeg
,从而M为
http://5b0988e595225.cdn.sohucs.com/images/20181218/91dc06675bdb4a369d89b29f735d05e0.jpeg
的中点。
http://5b0988e595225.cdn.sohucs.com/images/20181218/39821e000ba0475cb26276fdb9e1e2fd.jpeg
,M坐标为
直线
http://5b0988e595225.cdn.sohucs.com/images/20181218/91dc06675bdb4a369d89b29f735d05e0.jpeg
的方程为
http://5b0988e595225.cdn.sohucs.com/images/20181218/a1c55d3be3634dcaaab629160f4a3500.jpeg
。
即
http://5b0988e595225.cdn.sohucs.com/images/20181218/42b6b3cc6f8249578cfe7a3ce68363b6.jpeg
(*)
又由命题1得,
http://5b0988e595225.cdn.sohucs.com/images/20181218/2ddf1948b8a74ef8a15ad7ddea99ebe6.jpeg
方程为
http://5b0988e595225.cdn.sohucs.com/images/20181218/6bb1a06f9efc4d00bf119fc58d6db0d7.jpeg
方程为
http://5b0988e595225.cdn.sohucs.com/images/20181218/dae7b56b2d644be68bddd45fe5de0490.jpeg
。
由
http://5b0988e595225.cdn.sohucs.com/images/20181218/c56b6c0441794d54ad1f615e525d67b3.jpeg
,可得
http://5b0988e595225.cdn.sohucs.com/images/20181218/8f43e6f8c5ff4f5789c5bac31cf59a31.jpeg
http://5b0988e595225.cdn.sohucs.com/images/20181218/0b619122bfee457bab2d819b39b3e671.jpeg
代入(*)式得,切点弦
http://5b0988e595225.cdn.sohucs.com/images/20181218/91dc06675bdb4a369d89b29f735d05e0.jpeg
所在直线方程为
http://5b0988e595225.cdn.sohucs.com/images/20181218/6269f743c3d840b6bdf4b01075ddd4d6.jpeg
。

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