Latex中使用align来对齐多行公式的排版技巧


分类: LaTex |
转自:https://blog.csdn.net/rumswell/article/details/13505399
Latex代码如下:
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\documentclass{article}
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\pagestyle{empty}
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\setcounter{page}{6}
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\setlength\textwidth{266.0pt}
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\usepackage{CJK}
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\usepackage{amsmath}
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\begin{CJK}{GBK}{song}
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\begin{document}
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\begin{align}
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(a + b)^3 &= (a + b) (a + b)^2 \\ -
&= (a + b)(a^2 + 2ab + b^2) \\ -
&= a^3 + 3a^2b + 3ab^2 + b^3 -
\end{align}
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\begin{align}
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x^2 + y^2 & = 1 \\ -
x & = \sqrt{1-y^2} -
\end{align}
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This
example has two column-pairs. -
\begin{align}
\text{Compare } -
x^2 + y^2 &= 1 & -
x^3 + y^3 &= 1 \\ -
x &= \sqrt {1-y^2} & -
x &= \sqrt[3]{1-y^3} -
\end{align}
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This
example has three column-pairs. -
\begin{align}
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x &= y & X &= Y & -
a &= b+c \\ -
x' &= y' & X' &= Y' & -
a' &= b \\ -
x + x' &= y + y' & -
X + X' &= Y + Y' & a'b &= c'b -
\end{align}
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-
This
example has two column-pairs. -
\begin{flalign}
\text{Compare } -
x^2 + y^2 &= 1 & -
x^3 + y^3 &= 1 \\ -
x &= \sqrt {1-y^2} & -
x &= \sqrt[3]{1-y^3} -
\end{flalign}
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This
example has three column-pairs. -
\begin{flalign}
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x &= y & X &= Y & -
a &= b+c \\ -
x' &= y' & X' &= Y' & -
a' &= b \\ -
x + x' &= y + y' & -
X + X' &= Y + Y' & a'b &= c'b -
\end{flalign}
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-
This
example has two column-pairs. -
\renewcommand\minalignsep{0pt}
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\begin{align}
\text{Compare } -
x^2 + y^2 &= 1 & -
x^3 + y^3 &= 1 \\ -
x &= \sqrt {1-y^2} & -
x &= \sqrt[3]{1-y^3} -
\end{align}
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This
example has three column-pairs. -
\renewcommand\minalignsep{15pt}
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\begin{flalign}
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x &= y & X &= Y & -
a &= b+c \\ -
x' &= y' & X' &= Y' & -
a' &= b \\ -
x + x' &= y + y' & -
X + X' &= Y + Y' & a'b &= c'b -
\end{flalign}
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\renewcommand\minalignsep{2em}
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\begin{align}
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x &= y && \text{by hypothesis} \\ -
x' &= y' && \text{by definition} \\ -
x + x' &= y + y' && \text{by Axiom 1} -
\end{align}
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\begin{equation}
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\begin{aligned}
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x^2 + y^2 &= 1 \\ -
x &= \sqrt{1-y^2} \\ -
\text{and also }y &= \sqrt{1-x^2} -
\end{aligned}
\qquad -
\begin{gathered}
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(a + b)^2 = a^2 + 2ab + b^2 \\ -
(a + b) \cdot (a - b) = a^2 - b^2 -
\end{gathered}
\end{equation} -
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\begin{equation}
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\begin{aligned}[b]
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x^2 + y^2 &= 1 \\ -
x &= \sqrt{1-y^2} \\ -
\text{and also }y &= \sqrt{1-x^2} -
\end{aligned}
\qquad -
\begin{gathered}[t]
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(a + b)^2 = a^2 + 2ab + b^2 \\ -
(a + b) \cdot (a - b) = a^2 - b^2 -
\end{gathered}
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\end{equation}
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\newenvironment{rcase}
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{\left.\begin{aligned}} -
{\end{aligned}\right\rbrace} -
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\begin{equation*}
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\begin{rcase} -
B' &= -\partial\times E \\ -
E' &= \partial\times B - 4\pi j \, -
\end{rcase} -
\quad \text {Maxwell's equations} -
\end{equation*}
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\begin{equation}
\begin{aligned} -
V_j &= v_j & -
X_i &= x_i - q_i x_j & -
&= u_j + \sum_{i\ne j} q_i \\ -
V_i &= v_i - q_i v_j & -
X_j &= x_j & -
U_i &= u_i -
\end{aligned}
\end{equation} -
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\begin{align}
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A_1 &= N_0 (\lambda ; \Omega') -
- \phi ( \lambda ; \Omega') \\ -
A_2 &= \phi (\lambda ; \Omega') -
\phi (\lambda ; \Omega) \\ -
\intertext{and
finally} -
A_3 &= \mathcal{N} (\lambda ; \omega) -
\end{align}
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\end{CJK}
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\end{document}
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