各态历经假说(ergodic hypothesis)

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In
The ergodic hypothesis is often assumed
in
Liouville's Theorem
Dr. Shannon's work roots back, as von Neumann has pointed out, to Boltzmann's observation, in some of his work on statistical physics (1894), that entropy is related to "missing information," inasmuch as it is related to the number of alternatives which remain possible to a physical system after all the macroscopically observable information concerning it has been recorded. L. Szilard (Zsch. f. Phys. Vol. 53, 1925) extended this idea to a general discussion of information in physics, and von Neumann (Math. Foundation of Quantum Mechanics, Berlin, 1932, Chap. V) treated information in quantum mechanics and particle physics.
(The Mathematical Theory of Information, Claude Shannon and Warren Weaver, p. 3n)
Although the physical dimensions of thermodynamic entropy (joules/ºK) are not the same as (dimensionless) mathematical information, apart from units they share the same famous formula.
S = ∑ piTo see this very simply, let's consider the well-known example of a bottle of perfume in the corner of a room. We can represent the room as a grid of 64 squares. Suppose the air is filled with molecules moving randomly at room temperature (blue circles). In the lower left corner a small number of (red) perfume molecules will be released when we open the bottle (when you start the demonstration animation below).ln pi
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What is the quantity of information we have about the perfume molecules? At the start we know their location in the lower left square, a bit less than 1/64th of the container. The quantity of information is determined by the minimum number of yes/no questions it takes to locate them. The best questions are those that split the locations evenly (a binary tree).
For example:
- Are they in the upper half of the container? No.
- Are they in the left half of the container? Yes.
- Are they in the upper half of the lower left quadrant? No.
- Are they in the left half of the lower left quadrant? Yes.
- Are they in the upper half of the lower left octant? No.
- Are they in the left half of the lower left octant? Yes.
If the room had no air, the perfume would rapidly reach an equilibrium state, since the molecular velocity at room temperature is about 400 meters/second. Collisions with air molecules prevent the perfume from dissipating quickly. This lets us see the approach to equilibrium. When the perfume has diffused to one-sixteenth of the room, the entropy will have risen 2 bits for each molecule, to one-quarter of the room, four bits, etc.
Click here to start a
In 1877, Boltzmann simply ignored classical dynamics and instead
made the assumption that all phase space cells were equally
probable. Classical dynamics could not prove that the path of the
system in phase space would move through all the cells, let alone
spend equal time in all cells. Boltzmann described a system he
called "ergode," later called the canonical ensemble by J. Willard
Gibbs. Equal
Paul and Tatiana Ehrenfest made the ergodic hypothesis the central question in statistical mechanics. Mathematicians took up the problem of ergodicity in continuous mathematics, which has questionable relevance for problems in discrete particle physics.
In modern quantum statistical mechanics, the same ergodic
hypothesis (equiprobability of phase space cells) shows up in an
assumption about transition
probabilities
The matrix element for the A - B transition is the complex conjugate of the reverse transition B - A. This is called Fermi's Golden Rule, although it was first derived by Paul Dirac.
We can see how any system with equal transition probabilities to and from any other state will quickly establish equilibrium populations. If 1000 systems are in state A and none in B, the early transitions will overwhelmingly be from A to B. An equal number of transitions back from B to A is not likely until the populations of A and B are about the same.
That is the basic idea behind the statistical formulation of Boltzmann's H-theorem. When all phase space cells are equally populated, the number of ways this can be achieved (the number of microstates) is at its maximum. Although cell populations will fluctuate away from this equilbrium condition, it corresponds to the maximum entropy.
The Ergodic Hypothesis and Equipartition of Energy |
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One of the most important principles of physics is the principle of
the equipartition of energy, according to which the energy of a
system will tend to distribute itself equally over all the degrees
of freedom of the system. However, the equipartition of energy can
only be asserted with several qualifiers and provisos – even
classically. The equipartition principle relies on
the |
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Of course, it’s easy to conceive of circumstances in which this hypothesis doesn’t hold. For example, the energy surface in phase space may consist of multiple separate surfaces, making it impossible (classically) for a system to jump from one to the other. For another example, the path of the system may be periodic, visiting only points along some finite loop. More subtly, a system may evolve in an orbit that never precisely repeats, but it may nevertheless be confined to an “attracting orbit” within a sub-region of the surface. The ergodic hypothesis also requires that all the degrees of freedom be dynamically coupled, and that we exclude “special” initial conditions that lead to restricted orbits. Even for circumstances in which the ergodic hypothesis applies, the time scale over which the system can be expected to visit all regions may be so enormous that, for practical purposes, the ergodic hypothesis is not very relevant. (In view of all these exceptions, we might summarize by saying that the ergodic hypothesis is always valid, except when it isn’t.) |
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Another consideration regarding the ergodic hypothesis is the different ways in which a surface of constant energy may change as a function of the energy. Two possible cases are depicted below. |
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The weight factor assigned to each region on the surface E is proportional to the “thickness” between E and E+dE in that region, and in the left-hand figure this thickness is always non-zero and has the same sign, so it provides a well-defined density distribution. However, in the right-hand figure the two surfaces intersect, so that the “volume” between them has two different signs, and at the points of intersection the swept volumes for the regions around those points go to zero. Is it possible for surfaces of constant energy to exhibit this kind of behavior in phase space? If it is, then it’s not clear how the weight distribution could be normalized. Also, the locus of points with zero weight might be barriers, undermining the premises of the ergodic hypothesis. |
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All the same qualifiers on the applicability of the ergodic hypothesis apply to the principle of the equipartition of energy as well. In addition, from a physical standpoint, the “degrees of freedom” of any physical system are somewhat ambiguous and context-dependent, nut just because of non-linear modes, but also because there are no fully isolated systems. It has been noted by others that every atom is dynamically coupled with every other atom in the universe, at least by means of electromagnetic and gravitational fields. (which have infinite range). Gravitation, in particular, cannot be shielded, and couples to all forms of mass-energy. Nevertheless, equipartition of energy is one of the most important principles in both classical and quantum mechanics. |
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Usually we neglect the long-range interactions and focus on just
the local energy modes that are quadratic in the associated
coordinate or momentum. The usual generic “proof” of the
equipartition of energy in this context is based on the premise
that each of the generalized coordinates and momenta are
distributed according to a Maxwell-Boltzmann distribution. The
actual justification
for |
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At this point Maxwell referred to an analysis he had performed on
the scattering angles of colliding spheres, which had led him to
conclude that all directions of recoil are equally probable (in a
gas of randomly moving particles). From this he argued that all
directions of motion are equally probable, and therefore the
density must depend only on the magnitude of the speed, not on its
individual components. For example, the
density |
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Furthermore, since the distributions in the x, y, and z directions are statistically independent, Maxwell asserted that the density for any given speed must be proportional to the product of the densities of its components, i.e., |
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for some constant |
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where |
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Each of the integrals is equal to (p/b)1/2, so we have |
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Furthermore, given the density distribution (2) of velocities, we
can compute the mean values of any variables that depend only on
the velocity. For example, the mean value of
vx2 |
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Again the second two integrals each equal (p/b)1/2, and in addition the first integral evaluates to (p/b)1/2/(2b), so we have |
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By symmetry we get exactly the same mean values of
vy2 |
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To relate the constant |
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Now, if we have N such particles in the box, and we note that the pressure on each wall is the total force divided by L2, we see that the pressure on the walls will be |
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where the over-bar denotes the average. Since
Nm/L3 |
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Arguing that there is no preferential direction, the average velocity components in the three directions are equal (which implies that the average kinetic energies of a molecule in each of the three directions are equal), so the pressures on the walls are equal, and we have |
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(It’s debatable whether the particle velocities really are
perfectly isotropic when enclosed in a cubical container, but in
practice this turns out to be a fair assumption for most purposes.)
Recall that p = |
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Combining this with equation (3) and solving for the
constant |
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Inserting the values of a and b into equation (2), we arrive at the Maxwell-Boltzmann distribution |
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Since R = k/m, this can be written in the form |
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Thus the numerator of the exponent is just the sum of the translational kinetic energies in the three directions. We already know, from the previous equations, that the mean kinetic energy in each of the three directions is kT/2 (although it’s arguable that this was more or less an assumption), and this can easily be verified by integrating with the density function. |
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Moreover, it is argued that every energy mode has a distribution
density function of the same form as (4), from which it follows
that if the energy is a quadratic function of either the
generalized coordinates or the generalized momenta, then the mean
value of that energy mode (in equilibrium) is kT/2. This is the
principle of equipartition of energy. It may be somewhat surprising
at first that all the different species of energy modes, potential
as well as kinetic, all exhibit a Boltzmann distribution. For the
case of gravitational potential energy in an ideal gas this can be
established by a simple argument. As discussed
in |
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where g(z) and T(z) are the gravitational acceleration and temperature (respectively) at the height z. If we assume the temperature and the acceleration of gravity are constant over the range of interest, then the integral is just gh/T and we have |
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Since p = |
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Thus the density of molecules has a Boltzmann distribution over the range of potential energies, just as they do over the range of translational kinetic energies. For the case of potential energy we see that the distribution arises due to the simple fact that the molecules need to be more densely populated at the lower energy regions in order to produce the pressure to support the higher energy regions. |
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This makes it at least plausible that all the energy modes have a
Boltzmann distribution, and therefore the mean value of the energy
of each mode is kT/2. To show that this is mathematically
consistent, let’s consider a more general class of energy modes,
each of the form aq2 |
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The distribution is assumed to be of the Boltzmann form, so we have |
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More generally, consider the Hamiltonian |
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The mean value of any of the energy terms is found by an expression of the form |
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where the integrals are evaluated from negative to positive infinity. The first term on the right side is |
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Since this result doesn’t depend on the value of the coefficient “a”, it clearly applies to every quadratic energy term in the Hamiltonian, consistent with the claim that each degrees of freedom has the same average energy. |
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Of course, this result actually follows immediately from the premise that every energy mode has a Boltzmann distribution with parameter kT. In addition, we tacitly invoked the ergodic hypothesis by arguing that the system’s path on the energy-surface within phase space will, in the long run, visit each accessible region with a frequency proportional to the volume of the region. Naturally if the system’s path is periodic or bounded within a restricted orbit, or if the energy modes are not dynamically coupled, the ergodic hypothesis doesn’t apply. Furthermore, the actual energy modes of real physical systems are generally not simply quadratic. In addition, as alluded to previously, the tacit assumption that energy can take on any real value turns out to be false, due to quantum effects. For all these reasons, the specific heats of substances with complicated energy modes do not generally agree with the simplistic classical prediction. (They generally vary with temperature, and approach the classical prediction only at very high temperatures.) |
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It’s interesting that Maxwell’s deduction of the velocity distribution function works in three or two dimensions, but not in one dimension. Sure enough, it can be shown that the velocity distribution in one dimension does not approach the Maxwell distribution. This shows that the directional scattering which occurs in two or more dimensions is crucial. Regarding this distribution, Maxwell commented |
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It appears from this proposition that the velocities are distributed among the particles according to the same law as the errors are distributed among the observations in the theory of the “method of least squares”. The velocities range from 0 to ∞, but the number of those having great velocities is comparatively small. |
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Maxwell went on to show that, if two populations of particles (with different masses) are mixed, they will approach an equilibrium condition in which the average kinetic energy of each species of particle is the same. He might have made use of the mean-value integration presented above for the combined Hamiltonian, but instead he presented a pictorial and algebraic proof, which not only showed the equilibrium configuration but also gave a quantitative indication of how rapidly a system of particles would approach equilibrium. |
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Let M and m be the masses of the particles in the two populations,
and let v0 |
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This can be represented pictorially as the lengths of the edges of
a right triangle as shown below. (Note that this
is |
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The mean speed of the center of gravity of two particles, one from
each population, corresponds to the length of the interval from O
to G, where the point G is chosen with the appropriate weighting,
i.e., such that the ratio of the segments GA and GB is inversely
proportional to the masses. Combining the requirements
ug/vg |
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We can now solve for the length |
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After these two particles collide, their speeds relative to their center of gravity will be unchanged in magnitude, but the axis of their mutual recoil will be from a uniform distribution relative to the direction of their center of gravity (as Maxwell had shown previously). Therefore, the mean result is represented by placing the recoil speeds perpendicular to the segment representing the center of gravity, as shown in the figure below. |
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Consequently, the mean speeds of the two particles following the
collision are equal to the lengths of the segments Oa and Ob, which
are denoted by u1 |
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and therefore we have |
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This shows that the difference between the kinetic energies of the two particles is less following the collision than it was prior to the collision. The same argument applies to every collision, so the difference drops exponentially to zero. From this Maxwell concludes that the mean translational kinetic energies of any number of monatomic particles of any masses approach equality at equilibrium. Naturally this is consistent with the previous demonstration. |