在matlab中有两种除法:/和\,那么它们有什么区别呢?看了几本书,上面没有说或者是没有说明白,其实很简单,我们可以从英文帮助中查到:

A\B is the matrix division of A into B, which is roughly the
     same as INV(A)*B , except it is computed in a different way.

   所以:A/B=A*inv(B);

     A/B is the matrix division of B into A, which is roughly the
     same as A*INV(B) , except it is computed in a different way.
     More precisely, A/B = (B'\A')'.

所以:A\B=inv(A)*B;

他们之间的关系为:

A/B = (B'\A')'.

看来还是英文帮助比较实用.

举例如下:

    >> a=magic(3)

a =

      8      1      6
      3      5      7
      4      9      2

>> b=pascal(3)

b =

      1      1      1
      1      2      3
      1      3      6

>> a/b

ans =

     27    -31     12
      1      2      0
    -13     29    -12

>> a*inv(b)

ans =

     27    -31     12
      1      2      0
    -13     29    -12

>> a\b

ans =

     0.0667     0.0500     0.0972
     0.0667     0.3000     0.6389
     0.0667     0.0500    -0.0694

>> inv(a)*b

ans =

     0.0667     0.0500     0.0972
     0.0667     0.3000     0.6389
     0.0667     0.0500    -0.0694

>> a/b-(b'\a')'

ans =

      0      0      0
      0      0      0
      0      0      0