using namespace std;

class Kitty {
public:
    explicit Kitty(int toys) : m_toys(toys) { }

    void meow(const vector& v) const {
        for_each(v.begin(), v.end(), [this](int n) {
            cout << "If you gave me " << n << " toys, I would have " << n + m_toys << " toys total." << endl;
        });
    }

private:
    int m_toys;
};

int main() {
    vector v;

    for (int i = 0; i < 3; ++i) {
        v.push_back(i);
    }

    Kitty k(5);
    k.meow(v);
}

If you gave me 0 toys, I would have 5 toys total.
If you gave me 1 toys, I would have 6 toys total.
If you gave me 2 toys, I would have 7 toys total.

当你捕获了this以后，m_toys就可以使用了，它隐式的表示this->m_toys，你也可以显示的说明this->m_toys。（在lambda表达式中，只有捕获了this后才可以使用它，你永远无法得到lambda表达式本身的this指针）

你也可以隐式的捕获this：

using namespace std;

class Kitty {
public:
    explicit Kitty(int toys) : m_toys(toys) { }

    void meow(const vector& v) const {
        for_each(v.begin(), v.end(), [=](int n) {
            cout << "If you gave me " << n << " toys, I would have " << n + m_toys << " toys total." << endl;
        });
    }

private:
    int m_toys;
};

int main() {
    vector v;

    for (int i = 0; i < 3; ++i) {
        v.push_back(i);
    }

    Kitty k(5);
    k.meow(v);
}

C:\Temp>cl /EHsc /nologo /W4 implicitmemberkitty.cpp > NUL && implicitmemberkitty
If you gave me 0 toys, I would have 5 toys total.
If you gave me 1 toys, I would have 6 toys total.
If you gave me 2 toys, I would have 7 toys total.

你也可以使用“[&]”,但是它不会影响this的捕获方式（永远按值传递）。“[&this]”是不允许的。