从纯数学来讲，k线图的角度是不能严格成立的。因此只好模仿网上45度的k线图定义给出25度的atan：
N:=60;
ATN25:=0.4663;
JD2:(FILTER(ATAN(SLOPE(EMA((C+L+H)/3,N),2))*3.14159*10>ATN25,8) AND
EMA((C+L+H)/3,21)>REF(EMA((C+L+H)/3,8),1));

5日线呈大于45度的斜率向上翘起

X1X:=(C+L+H)/3;
X2X:=EMA(X1X,6); 
X3X:=EMA(X2X,5); 
BB13:=ATAN(EMA(X1X,13)-REF(EMA(X1X,13),1))*3.1416*10;
EMA8:=EMA(C,8);
DRAWTEXT(FILTER(BB13>1 AND EMA(X1X,13)>REF(EMA(X1X,8),1),10),
EMA8,'∠45上升'),COLORWHITE;