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第2.4节 反函数

(2013-08-15 14:11:44)
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杂谈

2.4  INVERSE  FUNCTIONS

     Two real functions f and g are called inverse functions if the two equations

y=f(x),   x=g(y)

Have the same graphs in the (x, y) plane. That is, a point (x, y) is on the curve y=f(x) if, and only if, it is on the curve x=g(y). (in general, the graph of the equation x=g(y) is different from the graph of y=g(x), but is the same as the graph of y=f(x); see Figure 2.4.1.)

wps_clip_image-8900

wps_clip_image-11668

Figure 2.4.1 inverse functions

For example, the function y=x², x ≥ 0, has the inverse function x=_______; the function y=x ³ has the inverse function x=______.

If we think of f as a black box operating on an input x to produce an output f(x), the inverse function g is a black box operating on the output f(x) to undo the work of f and produce the original input x  (see Figure 2.4.2).

wps_clip_image-14891

Figure 2.4.2

Many functions, such as y=x2, do not have inverse functions. In Figure 2.4.3, we see that x is not a function of y because at y=1, x has the two values x=1 and x= -1.

Often one can tell whether a function f has an inverse by looking at its graph. If there is a horizontal line y=c which cuts the graph at more than one point, the function f has no inverse. (see figure 2.4.3.) if no horizontal line cuts the graph at more than one point, then f has an inverse function g. Using this rule, we can see in figure 2.4.4 that the functions y=| x | and y = _______________ do not have inverses.

wps_clip_image-24960

Figure 2.4.3

wps_clip_image-18338

wps_clip_image-30344Figure  2.4.4                   No inverse functions

Table 2.4.1 shows some familiar functions which do have inverses.

wps_clip_image-9444Note that in each case,

wps_clip_image-3028

Suppose the (x, y) plane is flipped over about the diagonal line y=x. This will make the x-and y-axes change places, forming the (y,x) plane. If f has an inverse function g, the graph of the function y=f(x) will become the graph of the inverse function x=g(y) in the (y, x) plane, as shown in Figure 2.4.5.

The following rule shows that the derivatives of inverse functions are always reciprocals of each other.

INVERSE  FUNCTION  RULE

   Suppose f and g are inverse functions, so that the two equations

                    y=f(x)     and    x=g(y)

   have the same graphs. If both derivatives f '(x) and g '(y) exist and are nonzero,

wps_clip_image-22379

then                     

wps_clip_image-12320

that is,    

PROOF  Let Δx be a nonzero infinitesimal and let Δy be the corresponding change in y. Then Δy is also infinitesimal because f '(x) exists and is nonzero because f(x) has an inverse function. By the rules for standard parts,

wps_clip_image-32131

wps_clip_image-12548Therefore  

wps_clip_image-7418

wps_clip_image-31068

(a)

wps_clip_image-10327wps_clip_image-8240

(b)

wps_clip_image-30396wps_clip_image-4994

(c)

wps_clip_image-3038wps_clip_image-26353

(d)

Figure 2.4.5

wps_clip_image-14519The formula

in the Inverse Function Rule is not as trivial as it looks. A more complete statement is

____  computed with x the independent variable

= ________ computed with y the independent variabe.

Sometimes it is easier to compute dx/dy than dy/dx, and in such cases the Inverse Function Rule is a useful method.

EXAMPLE 1  Find dy/dx where x=1+y -3.

          Before solving the problem we note that

wps_clip_image-19475

     So x and y are inverse functions of each other. We want to find

wps_clip_image-8933

With x the independent variable. This looks hard, but it is easy to compute

wps_clip_image-10989

With y the independent variable.

SOLUTION   ____ = -3y -4,

wps_clip_image-28619

We can write dy/dx in terms of x by substituting,

wps_clip_image-17149

EXAMPLE  2  Find dy/dx where x= y5 + y3 + y. Compute dy/dx at the point(3,1).

       Although we cannot solve the equation explicitly for y as a function of x, we can see from the graph in Figure 2.4.6 that there is an inverse function y=f(x).

wps_clip_image-31217wps_clip_image-16809

Figure 2.4.6

By the Inverse Function Rule,

wps_clip_image-27192

This time we must leave the answer in term of y. At the point (3,1), we substitute 1 for y and get dy/dx = 1/9.

For y≥ 0, the function x= y n has the inverse function y= x1/n. In the next theorem, we use the Inverse Function Rule to find a new derivative, that of y= x1/n.

THEOREM  1

     If n is a positive integer and

y= x1/n.

wps_clip_image-24850     then                   

Remember that y= x1/n. is defined for all x if n is odd and for  x > 0 if n is even.

The derivative______ is defined for x≠ 0 if n is odd and for x > 0 if n is even.

If we are willing to assume that dy/ dx exists, then we can quickly find dy/dx by the Inverse Function Rule.

wps_clip_image-7134

Here is a longer but complete proof which shows that dy/dx exists and computes its value.

PROOF  OF  THEOREM 1

              Let x≠ 0 and let Δx be nonzero infinitesimal. We first show that

Δy= (x + Δx) 1/n - x1/n

           is a nonzero infinitesimal. Δy ≠ 0 because x+Δ x ≠ x. The standard part of

Δy is

st( Δy) = st(( x+ Δ x)1/n) - st(x1/n )

                                    =x1/n - x1/n = 0.

Therefore y is nonzero infinitesimal.

wps_clip_image-31391Now                  

wps_clip_image-10593

Therefore

wps_clip_image-4793

wps_clip_image-12742

Figure 2.4.7

Figure 2.4.7 shows the graphs of y=x1/3 and y=x1/4. At x =0, the curves are vertical and have no slope.

EXAMPLE  3  Find the derivatives of y=x1/n for n=2, 3,4.

wps_clip_image-20369

Using Theorem 1 we can show that the Power Rule holds when the exponent is any rational number.

POWER  RULE  FOR  RATIONAL  EXPONENTS

Let y=xr where r is a rational number. Then whenever x>0,

wps_clip_image-8400

PROOF  Let r=m/n where m and n are integers, n>0. Let

u=x 1/n,  y=um.

Then                __________________

wps_clip_image-6884and

EXAMPLE  4  Find dy/dx where

wps_clip_image-23076

EXAMPLE  5  Find dy/dx where

                        ______________________.

Let                 u=2+x3/2,   y= u -1.

wps_clip_image-28444Then          

PROBLEMS  FOR  SECTION 2.4

In Problems 1-16, find dy/dx.

1       x=3y3 + 2y                      2   x = y2 + 1,    y>0

3       x= 1 - 2y2 , y>0                  4   x=2y5 + y3 + 4

5       x= (y2 +2)-1 , y>0                 6   _______

7       y=x 4/3                                   8   _______

9       ____________                   10  y= (2x 1/3+ 1) 3 

11      y= 1+ 2x 1/3 + 4x 2/3 +6x  12  y=x -1/4 + 3x -3/4

13      y= (x 5/3 - x) -2                           14   x= y+_____

15     x= 3x 1/3 +2y,  y > 0               16      x= 1/(1 + ____)

In Problems 17-25, find the inverse function y and its derivative dy/dx as functions of x.

17    x=ky+c,  k≠ 0                     18    x= y3 + 1

19    x=2y2+1, y≥ 0                      20    x=2y2+1, y≤0   

21    x=y4 - 3, y≥ 0                       22    x=y2+3y-1,  y ≥ ____

23    x=y4+y2 +1 , y≥ 0                    24   x = 1/y2 +1/y -1 ,  y > 0  

25    _______________

□26  show that no second degree polynomial x= ay2 + by +c has an inverse function.

□27  show that x=ay2 + by + c, y ≥ -b/2a, has an inverse function. What does its graph look

      like?

□28  Prove that a function y=f(x) has an inverse function if and only if whenever x1≠ x2,

f(x1)__ f(x2)  

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